TUGAS EKONOMI TEKNIK (PART 1)

Jawab Soal :

1. NPW = - 120JT - 10JT (P/A,12%,8) + 30JT (P/A,12%,8) + 50JT (P/F,12%,8) - 15JT
              = -120JT - 10JT(4.968) + 30JT (4.968) + 50JT (0.4) - 15JT
              = - 15.64JT
Tidak layak karena NPW < 0

2. NPW = -50JT + 10JT (P/F,8%,8) + 15JT (P/A,8%,8) - ( 5JT + 0.3JT )(P/A,8%,8)
              = -50JT + 10JT(0.54) + 15JT(5.75) - 5.3JT(17.5)
              = 8.05JT
Layak, NPW > 0

3. NPV = -400JT - 25JT(P/A,10%,10) + 100JT (P/F,10%,10) + 80JT (P/A,10%,2) + 80JT(P/A,20%,10%,8)
             = -400JT - 25JT(6.14) + 100JT(0.38) + 80JT(1.74) + 80JT(10.1)
             = 374.24JT
Layak, NPV > 0

4. AW =R -E -CR
           = { 300JT (P/G,16,66%,10%,6) + 600JT(P/A10%,6) - 23JT(P/G,10%,6)} - {50JT(P/A,20%,10%,8) + 130JT(P/A,10%,4) + 150JT(P/F,10%,1)} - 2M
           = { 300JT (6.35) + 600JT(4.35) - 23JT(9.68)} - {50JT (10.1) + 130JT(3.17) + 150JT(0.19)} - 2M
           = 1.2194M

AW >= 0, Layak.

5. RoR = [{ (267x72) - 14500 } / 14500 ] x 100%
            = 32.58%